10p^2+7p+1=0

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Solution for 10p^2+7p+1=0 equation: 



10p^2+7p+1=0

a = 10; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·10·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*10}=\frac{-10}{20}
=-1/2
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*10}=\frac{-4}{20}
=-1/5
$

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